Method of False Position Calculator

This page contains an online step-by-step interactive calculator for the Method of False Position which is also known as the Regula-Falsi Method. For a detailed explanation, please visit this page.

Given,

$y=f(x)=$

Interval: $x_0 =$to$x_1 =$

Error threshold$(e)=$

Solution,

Check whether the interval brackets a solution:

$$f(x_0)=f(1)=(1)^3-2=-1$$

$$f(x_1)=f(2)=(2)^3-2=6$$

Since $f(x_0)\times f(x_1)=-6\leq 0$, the interval brackets a solution and hence we can proceed further.

$n$	$a$	$b$	$f(a)$	$f(b)$	$x_n=(a+b)/2$	$f(x_n)$	Assign
$1$	$1$	$2$	$-1$	$6$	$1.143$	$-0.507$	$a=x$
$2$	$1.143$	$2$	$-0.507$	$6$	$1.21$	$-0.23$	$a=x$
$3$	$1.21$	$2$	$-0.23$	$6$	$1.239$	$-0.099$	$a=x$
$4$	$1.239$	$2$	$-0.099$	$6$	$1.251$	$-0.041$	$a=x$
$5$	$1.251$	$2$	$-0.041$	$6$	$1.256$	$-0.017$	$a=x$
$6$	$1.256$	$2$	$-0.017$	$6$	$1.258$	$-0.007$	$a=x$
$7$	$1.258$	$2$	$-0.007$	$6$	$1.259$	$-0.003$	$a=x$

Therefore, the solution is at $x=1.259$